EASA Part-66 Exam Preparation Online

Yeah this one's tricky, the V squared over R rule does work but only if you use the voltage across that resistor, not the full 200 V. The two resistors are in series so the 200 V splits between them, 50 V over the 10 k and 150 V over the 30 k, and 50 squared divided by 10000 gives 0.25 W, which is the 250 mW option. Think of it like water pressure dropping along a hose, the bit of pressure lost over the first section is what does the work there, not the pressure back at the tap. Easier still is to find the current first, 200 V over 40 k is 5 mA, then P equals I squared R gives the same 250 mW.

Lisa_T replied to mounirfouina's question ·2h ago

which rule is used here ! p=V square over R

mounirfouina asked a question ·6h ago

Actually, option 1 is not incorrect due to missing keywords, it is incorrect due to scope. It limits the aim to occupational health and accident prevention, whereas a human factors programme addresses the interaction of personnel with equipment, procedures and environment, and therefore targets operational safety and efficiency as well as personal well-being.

svenj88 replied to wan.yc.justin's question ·2d ago

#1 being wrong is it because of the missing of keywords?

wan.yc.justin asked a question ·2d ago

2 dots equals 4 degrees. Each point represent 2 degrees and full deflection is 10 degrees

khalidjat asked a question ·5d ago

You are right, the stem is too broad. On a conventional turboprop the power lever runs to the fuel control unit and a separate lever sets the governor, so option A fits that case perfectly well. I am rewording the stem to name the single lever installation, which is the only one the marked answer describes. Thanks for flagging it.

PART66Online replied to josh93's question ·11d ago

What about a king air 200? The power control lever only operates the FCU via the connecting rod. The prop is controlled via a separate lever. That lever only controls the primary governor. So this question is not accurate. Not all aircraft have FADEC! A&B can be correct for this question so maybe it should read "on a modern turboprop aircraft the power lever controls?"

josh93 asked a question ·11d ago

Good addition, thanks. 2n^2 gives 2 for the first shell and 8 for the second. I have added the formula to the question explanation for clarity.

PART66Online replied to BurtoJ's question ·15d ago

Formula = 2n^2 (where n = Shell #)

BurtoJ asked a question ·16d ago

Good catch, and thanks for citing the source rather than just the number. You are right about the AESA guide, so I went and checked the rule itself. Part-66 does not set a submission window at all. Point 66.A.40 and point 66.B.120 require only that EASA Form 19 and your copy of the licence reach the competent authority that issued it, and AMC 66.B.120 adds no time limit either. The only 30, 60 and 90 day periods written into Annex III are the examination retake waiting periods, which is a different subject entirely. So the period is national, and it varies more than I expected. The UK CAA will not accept an application earlier than 60 days before expiry. Spain, the Netherlands and Finland all work to 3 months. Italy asks for at least one month and will still renew a licence that expired long ago. They are not even the same kind of rule, the UK figure is a ceiling and the Spanish one is a floor, so 60 days would actually be late for you. Question fixed. The 60 day option has been rep…

PART66Online replied to ALEX LORENCIO's question ·24d ago